6.00 AC 150 HC -2.00 500 cm 200 cm Need Help? R Rand s. O 020 points prenous Anw

Question

6.00 AC 150 HC -2.00 500 cm 200 cm Need Help? R Rand s. O 020 points prenous Anwert sercp11 15 P011 ML Three charges are arranged as shown in the figure below. Find the magnitude and direction of the electrostati magnitude law to find the force that each charge exerts on the charge at the origin and com wise from the +x axis 6.00 nC 0,100 m -3.00 mC Need Help? submit Answer Save Progress ractice Another Version Previous Answers sercP11 15 P013 Three point charges are located at the corners of an equilateral triangle as in the figure below. Find the magnitud 2017 Baptist

Explanation / Answer

Force on q due to + 6.00 nC charge
= - 9 x 10^9 * 4.92 x 10^-9 * 6.0 x 10^-9 / (0.260)^2 i N
= - 0.00000393 i N

Force on q due to - 3.00 nC
= - 9 x 10^9 * 4.92 x 10^-9 * 3.0 x 10^-9 / (0.1)^2 j N
= - 0.00013284 j N

Magnitude
= [( 0.00000393)^2 + (0.00013284)^2] N
= 0.0001328 N

Direction
= 180° + arctan[(0.0001328)/(0.00013284)]
= 225°.

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