Three charges are arranged in the (x, y) plane as shown. What is the magnitude o

Question

Three charges are arranged in the (x, y) plane as shown. What is the magnitude of the resulting force (in nano-Newtons) on the -4 nC charge at the origin? The Coulomb constant is 8.98755 times 10^9 N middot m^2/C^2. Answer in units of nN. What angle does the resultant force on the -4 nC charge at the origin make with the positive x axis? Quadrant I lies between 0 degree and 90 degree, quadrant II between between 90 degree and 180 degree, etc. Answer in units of degs. Three positive charges are arranged as shown.

Explanation / Answer

here,

q1 = - 5 * 10^-9 C

q2 = - 4 * 10^-9 C

q3 = - 6 * 10^-9 C

21)

the net force on q2 , F = - F23 i - F21 j

F = - k * q2 * q3/9^2 i - k * q2 * q1 /8^2 j

F = - 9 * 10^9 * 6 * 10^-9 * 4 * 10^-9/81 i - 9 * 10^9 * 4 * 10^-9 * 5 * 10^-9 /64 j

F = (- 2.67 i - 2.81 j) * 10^-9 N

the magnitude of force , F = sqrt(2.67^2 + 2.81^2 ) * 10^-9 N

F = 3.87 * 10^-9 N

the magnitude of force is 3.87 * 10^-9 N

22)

x and y components are negative

then it lies in 3rd quadrent

direction of force , theta = arctan(2.81/2.67)

theta = 226.4 degree counterclockwise from +x axis

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