Three charged particles are placed at each of three corners of an equilateral tr

Question

Three charged particles are placed at each of three corners of an equilateral triangle whose sides are of length 3.3 . Two of the particles have a negative charge: = -7.6 and = -15.2 . The remaining particle has a positive charge, = 8.0 . What is the net electric force acting on particle 3 due to particle 1 and particle 2?Find the net force acting on particle 3 due to the presence of the other two particles. Report you answer as a magnitude and a direction measured from the positive x axis.
Express the magnitude in newtons and the direction in degrees to three significant figures.

Explanation / Answer

I am going to assume that 3.3 is in cm as they have been for me. And the charge on the particles are in Coulombs (i.e. -7.6x10^-6). Since you did not put your units it is hard for me to determine. I will simply use common sence.

Force = K(Q1(Q2))/(r^2)

K= 8.99x10^9 Nm^2/C

Force from particle 1 is -501.92 N

Force from particle 2 is -1003.84 N

Now apply C^2= A^2+B^2

Magnitude is 1122.32 N

tan()= y/x = 63.4 degrees. Since both of the values are negative our answer will be in quadrant 3 so we must add that number to 180 degrees. Which is 243 degrees.

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