In case E a positive point charge with +Q is a distance s away from a third posi

Question

In case E a positive point charge with +Q is a distance s away from a third positive point charge +q. In ease F ten positive point charges, each with charge +Q/10, lie along an arc of radius s centered on a positive point charge +q. Is the net electric force on the +q charge in case E greater than, less than, or equal to the net electric force on the +q charge in case F? Explain. A thin semicircular rod has a total charge +Q uniformly distributed along it. A negative point charge -Q is placed as shown. A test charge +q is placed at point C. (Point C is equidistant from -Q and from all points on the rod.) Let F_P and F_R represent the force on the test charge due to the point charge and the rod respectively. Is the magnitude of F_P greater than, less than, or equal to the magnitude of F_R Explain how you can tell. Is the magnitude of the net force on +q greater than, less than, or equal to the magnitude of F_P? Explain. A second negative point charge -Q is placed as shown. Is the magnitude of the net electric force on +q greater than, less than, or equal to the magnitude of the net electric force on +q in part b? Explain.

Explanation / Answer

The net electric Force on the +q charge in Case E and Case F will be SAME.

This is because - in case F for every charge there is another charge which will cancel the force in y-direction and add the force in the x-direction and when we take there sum it will come out to be same in the x-direction.

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