A charge of 3.40 C is held fixed at the origin. A second charge of 3.40 C is rel

Question

A charge of 3.40 C is held fixed at the origin. A second charge of 3.40 C is released from rest at the position (1.25 m, 0.570 m).

Part A

If the mass of the second charge is 2.97 g , what is its speed when it moves infinitely far from the origin?

SubmitMy AnswersGive Up

Part B

At what distance from the origin does the second charge attain half the speed it will have at infinity?

A charge of 3.40 C is held fixed at the origin. A second charge of 3.40 C is released from rest at the position (1.25 m, 0.570 m).

Part A

If the mass of the second charge is 2.97 g , what is its speed when it moves infinitely far from the origin?

SubmitMy AnswersGive Up

Part B

At what distance from the origin does the second charge attain half the speed it will have at infinity?

Explanation / Answer

Distance between the charges,
r = sqrt ( 1.25^2 + 0.7570^2 )
= 1.373 m

Potential energy of the second charge w.r.t. the first charge, kqq' / r gets fully converted into kinetic energy, (1/2) mv^2 at an infinite distance.

kqq'/r = (1/2) mv^2

v = sqrt (2kqq' / ( r*m )
= sqrt [ 2 ( 9*10^9 ) ( 3.40*10^-6 ) ( 3.40*10^-6 ) / ( 1.373 ) ( 0.00297 )

= 7.14 m/s .........................................PART A)

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.