iPad 3:45 PM e edugen wileyplus. com ysics, Practice Gradebook ORION Assignment

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iPad 3:45 PM e edugen wileyplus. com ysics, Practice Gradebook ORION Assignment ssignment UNTER VERSION BACK NEXT CES Chapter 19, Problem 45 Refer to 45 for one approach to this problem. The electronic flash attachment for a camera contains capacitor for storing the energy used to produce the flash. In one such unit, the potential difference between the plates of an 700-vF capacitor is 350 V. (a) Determine the energy that is used to produce the flash in this unit. (b) Assuming that 4l the flash lasts for 4.0 ms, find the effective power or "wattage" of the flash. (a) Number Units (b) Number Units Click if you would like to show work for this question Qpen Show Work By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor. Question Attempts: o of 4 used SAVE OR LATER SUBMET ANSWER nn Maximum Points available only if you answer this question correctly in four attempts or less. Copyright 2000-2017 by John Wiley & Sons, Inc. or related companies. All rights reserved Privacy Policy I R 2000 2017 John Wilcy& Sons Inc. All Rights Reserved. A Division of John Miley Sonsinc. 4.22.1.2

Explanation / Answer

Here,
capacitance, C = 700 uF  = 700 * 10 ^ - 6 F
potential difference, V = 350 V

Energy, E = ?
time, t = 4* 10^-3 s
Power, P = ?

(a) We know,
E = 1/2 CV^2  = 1/2 * 700 * 10 ^ -6 * (350)^2 = 42.875 Joule

(b) We know,
P = E/t
or, P = 42.875/(4*10^-3)
so, P = 10718.75 Watt

Hope this was helpful.

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