iPad 1:51 PM * 100%- zy 12.4. For loops ×\' D upcoming Events X\' % Integration
ID: 1782649 • Letter: I
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iPad 1:51 PM * 100%- zy 12.4. For loops ×' D upcoming Events X' % Integration of trig ×,. Practice Another x' D wv WileyPLUS C https://edugen.wileypius.com/edugen/student/mainfr.uni WileyPLUS: MyWileyPLUSI Help Contact Us1 Log Out WileyPLUS Haliay, Fundamentals of Physics PHYSICS FOR SCIENCE AND ENGINEERING (PHYS 2110/2120) 10e Home Read, Study& Practice Gradebook ORION Downloadable eTextbook Assignment> Open Assignment FULL SCREEN PRINTER VERSION BACK NEXT ASSIGNMENT RESOURCES Chapter 10, Problem 013 A flywheel turns through 34 rev as it slows from an angular speed of 8.3 rad/s to a stop. (a) Assuming a constant angulan acceleration, find the time for it to come to rest. (b) What is its angular acceleration? (c) How much time is required for it to complete the first 17 of the 34 revolutions? (a) Number (b) Number (c) Number Click if you would like to Show Work for this question: Open Show Work Units 028 041 050 062 Review Score Review Results by Study By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your Question Attempts: 0 of 5 used SAVE FOR LATER SUBMIT ANSWER Earn Maximum Points available only if you answer this question correctly in four attempts or less.Explanation / Answer
(b) wf^2 = wi^2 + 2aS
here
wf = final angular speed = 0 (rest)
wi = initial angular speed = 8.3 rad/s
S = 34 x 2pi radian
0 = (8.3)^2 + (2 x a x 34 x 2 pi)
427.256601 a = -68.89
a = -0.161 rad/s^2 (Answer)
(a) wf = wi + at
0 = (8.3) + (-0.161 x t)
.161t = 8.3
t = 51.55 sec (Answer)
(C) S = wi t + 1/2 a t^2
17 x 2 pi = 8.3 t + 1/2 (-.161) t^2
106.81415 = 8.3 t - 0.0805 t^2
0.0805 t^2 - 8.3 t + 106.81415 = 0
Solving the quadratic equation
t = 15.07 sec (Answer)
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