Suppose two children push horizontally, but in exactly opposite directions, on a

Question

Suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. The first child exerts a force of 68.0 N, the second exerts a force of 93.0 N, friction is 20.0 N, and the mass of the third child plus wagon is 23.0 kg. What is the system of interest if the acceleration of the child in the wagon is to be calculated? (Select all that apply.) the child in the wagon the children outside the wagon the wagon Calculate the acceleration (in m/s2). (Enter the magnitude.) m/s^2 What would the acceleration be (in m/s2) if friction were 25.0 N? (Enter the magnitude.) m/s^2

Explanation / Answer

(a) What is the system of interest if the acceleration of the child in the wagon is to be calculated?

the child in wagon

the children outside the wagon

the wagon

Fnet = Fr - F1 - f

Fnet = [(93 N) - (68 N) - (20 N)]

Fnet = 5 N

(b) The acceleration will be given as :

we know that,   Fnet = Fr - F1 - f

m a = Fr - F1 - f

a = [(93 N) - (68 N) - (20 N)] / (23 kg)

a = (5 N) / (23 kg)

a = 0.217 m/s2

{ in the direction of second child’s push }

(c) If friction were 25 N, then it's acceleration would be given as :

we know that,   Fnet = Fr - F1 - f

m a = Fr - F1 - f

a = [(93 N) - (68 N) - (25 N)] / (23 kg)

a = 0 m/s2

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