A projective is fired horizontally outward from the top of a table. The initial

Question

A projective is fired horizontally outward from the top of a table. The initial height of the bullet above the ground is 1.5 meters and the Buller travels a horizontal distance of 3.0 meters before striking the ground Calculate the time that the bullet was in the air muzzle (initial velocity of the bullet. An object of mass 5.0 kg reviles at 600 rpm in a horizontal circle of radius 1.5 m Determine the period of the object's motion in seconds' object's speed magnitude of the S A 2.0 kg object is released from rest from the top of a 5.0 m long frictionless incline. The angle of the McRae is 30" above the horizontal Calculate the object's a) velocity at the bottom of the incline. b) rate of acceleration and c) time required for the object to reach the bottom. In the ballistic pendulum experiment. a 0.50 kg bullet was fired at 9.9 m/s horizontally into a 2.00 kg pendulum which was initially at rest. The collision was completely inelastic. Determine the maximum height the bullet + pendulum reached above their initial position. In an experiment using the air track, a 3.0 kg glider moving at 2.0 m/s struck a 2.0 kg glider which was initially at refl. The collision was completely inelastic and after impact the two gliders moved together. Determine the velocity of the two gliders just after impact. A sphere of mass 2.0 kg is released from rest and rolls without slipping down a 5.0 m long inches. The angle of the incline is 10 degree. Calculate the sphere s a) tangential speed at the bottom, b) rate of acceleration, and c) time to travel from the top to the bottom.

Explanation / Answer

1) a ) t = sqrt(2h/g) = 2 sec

b) v = sqrt(2gh) = 19.6 m/s

2) a = 50 i

b = 100 j

r = 50i+100j

r = sqrt(a^2+b^2) = 111.8 lbs

3) a = -100i

b = -200 j

r = -100i-200j

r = sqrt(100^2+200^2) = 223.6 lbs

4) h = 1.5 m

x = 3 m

a) h = 1/2gt^2

t = sqrt(2h/g) = 0.55 sec

c) x = ut

u = x/t = 5.45 m/s

5) x = ux*t

t = 2usin30/g = 2*10*1/2/10 = 1 sec

x = 10cos30*1 = 8.66 m

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