The sled in the figure below is stuck in the snow. A child pulls on the rope and
ID: 1536798 • Letter: T
Question
The sled in the figure below is stuck in the snow. A child pulls on the rope and finds that the sled just barely begins to move when he pulls with a force of 27 N, with the rope at an angle of = 33° with respect to the horizontal. The mass of the sled is 10 kg.
(a) Sketch the sled and all the forces acting on it.
(b) Determine the components of all the forces on the sled along the coordinate axes. (Enter the magnitude only.)
mg
The normal force N will be in the : +x, x, +y, or y direction. (which one)
The friction force will be in the: +x, x, +y, or y direction. (which one)
(c) Write the conditions for static equilibrium along your two coordinate directions. (Use the following as necessary: Tx, Ty, m, g, Ffriction, and N and indicate the direction with the signs of these values.)
(d) What is the coefficient of friction between the sled and the snow?
(e) Is this the coefficient of static friction or the coefficient of kinetic friction?
(f) If the child continues to pull on the sled and it has an acceleration of 0.34 m/s2, find the coefficient of kinetic friction between the sled and the snow.
mg
= ____ N Ffriction = _____N AN pull friction gravExplanation / Answer
Tx = 27 * cos(33)
Tx = 22.644 N
Ty = 27 * sin(33)
Ty = 14.705 N
mg = 10 * 9.8
mg = 98 N
Ffriction = Tx
Ffriction = 22.644 N
The normal force N will be in the +y direction
The friction force will be in the -x direction
Fx = Tx - Ffriction = 0
Fy = N + Ty - mg = 0
Ffriction = k * (mg - Ty)
22.644 = k * (98 - 14.705)
k = 0.2718
corfficient of friction = 0.2718
this is the coefficient of kinetic friction
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