Given B square coil =1.13 x 10 -4 * I (Tesla), what is the value of the horizont

Question

Given   Bsquare coil =1.13 x 10-4*I (Tesla), what is the value of the horizontal component of Earth's magnetic field, Bearth, (in Gauss), if, at a current I= 0.17 A through a tangent galvanometer with a square coil, the angle between Bearth and Bnet is =58 degrees? Express the answer (without unit) to two decimal place.

QUESTION 1 5 points Save Answer Given Bsquare coil 1.13x lor4 , esla what is the value of the horizontal component of Earth's magnetic field. Bearth (in Gauss if at a current l= 0.17 A through a tangent galvanometer with a square coil, the angle between Bearth and Bnet is 8-58 degrees? Express the answer (without unit) to two decimal place. square coi Question Completion Status: Barth

Explanation / Answer

SOLUTION

tan()= Bcoil/Bearth              =58°

Bcoil= 1.13 X 10-4 * I

I= 0.17 A

So Bcoil= 1.13 X 10-4 * 0.17 = 1.921 X 10-5 T

Hence Bearth = Bcoil/tan= 1.921 X 10-5/tan(58) = 1.200 X 10^(-5) T

Hence the horizontal component of earth’s magnetic field is 1.200 X 10^(-5) T

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