5. O 35 points My Notes A simple Atwood machine consists of two masses m1 and m2
ID: 1538081 • Letter: 5
Question
5. O 35 points My Notes A simple Atwood machine consists of two masses m1 and m2 that are connected by a string wound over a pulley, as seen in the figure below. Assume m2 is larger than m Motion in the upward direction Is positive. On a plece of paper, draw two free body diagrams; one for each of the masses, showing all forces acting on each mass. Then answer the following questions. (a) Identify the forces acting on the mass m Select all that apply. mla m2a m19 m2g m1 m2)a (m2 m2)gy sing the direction rosette Indirate the directlan for ea ch of the forces acting on m hat dentified in nart If any of the forres listed below is not annlirahle choose 'NAExplanation / Answer
(a)
m1a
m1g
T
(b)
m1a = upwards
m2a = NA
m1g = downwards
m2g = NA
(m1+m2)*a = NA
(m1+m2)g = NA
f = NA
T = upwards
FN = NA
=======================
(c)
m2a
m2g
T
=======================
(d)
m1a = NA
m2a = downwards
m1g = NA
m2g = downwards
(m1+m2)*a = NA
(m1+m2)g = NA
f = NA
T = upwards
FN = NA
===========================
(e)
T - m1g = m1a
=================
(f)
T - m2g = -m2a
=====================
(g)
e/f
(T - m1g)/(T-m2g) = -m1/m2
m2*T - m2*m1*g = -m1*T + m1*m2*g
T = 2*m1*m2*g/(m1+m2)
=================
(h)
a = (m2-m1)*g/(m1+m2)
=================
(i)
mass m1 upwards
mass m2 downwards
-=---------------------------------
(j)
T = 2*5*9*9.8/(5+9) = 63 N
===================================
(k)
a = (9-5)*9.8/(5+9) =2.8 m/s^2
===========================
(l)
y = v0y*t + (1/2)(ay*t^2
-15 = 0 - (1/2)*2.8*t^2
t = 3.27 s
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