A 2.0 resistor is connected across a 6.0 V power supply. An ammeter with interna

Question

A 2.0 resistor is connected across a 6.0 V power supply. An ammeter with internal resistance of 1.0 is used to measure the current in this circuit. What is the ammeter reading?

A. 2.0 A

B. 4.0 A

C. 3.0 A

D. an ammeter with less resistance than the rest of the circuit will not produce a reading

E. 1.0 A

Four 12 resistors are connected together. Which of the following resistances cannot be formed using all 4 resistors?

A.20

B.9.0

C.48

D.60

E.12

An electron is moving at 3.6 × 106 m/s perpendicular to a uniform magnetic field. If the radius of the path is 18 mm, what is the magnitude of the magnetic field?

A.9.3 mT

B.1.1 mT

C.70 mT

D.8.9 nT

E.1.6 T

Which of the following statements is true?

A.electric field lines are perpendicular to equipotential surfaces

B.equipotential surfaces intersect in straight lines

C.equipotential surfaces intersect in curved lines

D.electric field lines stay inside equipotential surfaces

E.equipotential surfaces are parallel to each other

Three point charges are located on the x-axis. The first charge, q1 = 10.0 µC, is at x = -1.00 m; the second charge, q2 = 20.0 µC, is at the origin; and the third charge, q3 = -30.0 µC, is located at x = 2.00 m. What is the force on q2?

A.1.65 N in the negative x-direction

B.4.80 N in the positive x-direction

C.1.50 N in the negative x-direction

D.4.65 N in the negative x-direction

E.3.15 N in the positive x-direction

Explanation / Answer

here

the ammeter will always connect in series with resistance

so the total resistance of the circuit is

Req = 2 + 1

Req = 3 ohm

then the reading of ammeter is

I = V / R

I = 6 / 3

I = 2 amp

so the correct option is A) 2 A

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