Could you solve this question for me? The figure below shows five resistors and

Question

Could you solve this question for me?

The figure below shows five resistors and two batteries connected in a circuit. What are the currents I_1, I_2, and I_3? (Consider the following values: R_1 = 1.20 Ohm, R_2 = 2.18 Ohm, R_3 = 3.10 Ohm, R_4 = 4.04 Ohm, R_5 = 6.20 Ohm. Due to the nature of this problem, do not use rounded intermediate values in your calculations-including answers submitted in WebAssign. Indicate the direction with the sign of your answer.) I_1 1.31348 = A I_2 1.4123 = A I_3 -0.0988 = A

Explanation / Answer

Writting the loop equation for the upper loop,

120 - I1*R5 - I1*R3 - I3*R2 = 0 -----------(i)

Writting the loop equation for the lower loop,

9+I3*R2-I2*R4-I2*R1 = 0 --------------(ii)

Writting other equation,

I1-I2 = I3 --------------(iii)

adding equation i and ii,

129 = (R3+R5)*I1 + (R1+R4)*I2 => 9.3*I1 + 5.24*I2 = 129

from equation i and iii,

120 = (R5+R3+R2)*I1 - R2*I2 => 11.48*I1 - 2.18*I2 = 120

Solving equation we get, I1 = 11.3145 A and I2 = 4.53721 A and I3 = 6.77729 A

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