3) Here is a link discussing the atomic mass unit: https://www.thoughtco.com/def

Question

3) Here is a link discussing the atomic mass unit:

https://www.thoughtco.com/definition-of-atomic-mass-unit-amu-604366

Make sure to notice the conversion from atomic mass units to

kilograms. Find the mass for the following molecules and list them

in both amu and kg:

a. Proton

b. Neutron

c. Deuterium nucleus

d. Helium three nucleus (2 protons and 1 neutron)

e. Helium four nucleus (2 protons and 2 neutrons)

4) Here is a link discussing the mass defect:

http://physics.bu.edu/~duffy/sc546_notes10/mass_defect.html

Look over the calculation for Carbon 12.

5) Find the mass defect for the three nuclei from question (3). Give

the value in amu. Convert these to MeV (this will give you the

binding energy) using the link from question (4).

6) Finally, use Google (or your favorite search engine) to find how

much energy is needed to run a 100 watt light bulb for one hour.

Convert this to MeV and compare with the binding energy from

the previous question. Are the values similar or different? Would

this be a good way to power a light bulb? Why or why not?

7) Write a two or three paragraph conclusion. Be sure to include

parts you found interesting or are still confused about.

Explanation / Answer

a. proton

mass in a.m.u=1.007276 u and mass in kg = 1.6726*10^-27kg

b. Neutron

mass in a.m.u= 1.008665 and mass in kg= 1.6750*10^-27kg

c. Deutirium Nucleus

mass in a.m.u =2.014 and kg=3.36338*10^-27kg

d. Helium nuclus(2,1)

mass in amu= 3.016u and in kg= 5.008*10^-27kg

e. Helium nucleus(2,2)

in amu= 4.00162 and in kg=6.6448*10^-27kg

5. Mass defect calculation

Now the mass of 2 protons in amu =2* 1.007276 u

Now the mass of 1 nutron in amu=1.008665u

total mass of individal particles = 3.023217u

mass of He-3 = 3.016u

the mass difference= 3.023217-3.016=0.0072u

this mass defect equivilant to 0.0072 *931.5 Mev energy or = 6.7 Mev energy

6. 100 watt will use 100 joules / sec or 36000 joule in one hour

we know that 1joule = 6.24*10^18 ev

so 36000 joule = 2.3 * 10^23 electron volt.

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