A ring of charge is centered at the origin in the vertical direction. The ring h

Question

A ring of charge is centered at the origin in the vertical direction. The ring has a charge density of = 5.95 × 10-6 C/m and a radius of R = 2.57 cm. Find the total electric field, E, of the ring at the point P = (2.25 m, 0.00 m). The Coulomb force constant is k = 1/(4 0) = 8.99 × 109 N·m2/C2. A ring of charge is centered at the origin in the vertical direction. The ring has a charge density of = 5.95 × 10-6 C/m and a radius of R = 2.57 cm. Find the total electric field, E, of the ring at the point P = (2.25 m, 0.00 m). The Coulomb force constant is k = 1/(4 0) = 8.99 × 109 N·m2/C2.

Explanation / Answer

electric field is E = 2*pi*lamda*K*R*x/(x^2+R^2)^(3/2)

Given that lamda = 5.95*10^-6 C/m

k = 9*10^9

R = 0.0257 m

x = 2.25 m

then E = 2*pi*lamda*K*R*x/(x^2+R^2)^(3/2)

E = 2*3.142*5.95*10^-6*9*10^9*0.0257*2.25/(2.25^2+0.0257^2)^(3/2)

E = 1.707*10^3 N/C

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