A rigid square wire carries of I = 5.90A. The wire runs between the north and so

Question

A rigid square wire carries of I = 5.90A. The wire runs between the north and south poles of 8 small magnets stacked together and held at a constant elevation as shown in the above diagram, where each magnet has a thickness of t = /8 = 1.55cm and a magnetic field |B| = 0.119T between the poles. (a) If the wire is hanging in equilibrium, then what is the mass of the rigid wire? (b) If a nonmagnetic mass of mh = 14.5g is hung from the bottom of the wire, then by what factor must the current be increased to remain in equilibrium?

Explanation / Answer

M = (i L B)/g = (5.9*0.119*8*1.55e-2)/9.8 = 0.00888 Kg

b)

(14.5e-3 + 0.0088837)/0.0088837 * 0.119 = 0.313 T

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