A 25-kg crate is pulled up a ramp 25 m long and 3 m high by a constant force of

Question

A 25-kg crate is pulled up a ramp 25 m long and 3 m high by a constant force of 120 N that is applied parallel to the ramp. the crate starts from rest and has a velocity of 1.5 m/s when it reaches the top of the ramp. what is the frictional force between the crate and the ramp? A 25-kg crate is pulled up a ramp 25 m long and 3 m high by a constant force of 120 N that is applied parallel to the ramp. the crate starts from rest and has a velocity of 1.5 m/s when it reaches the top of the ramp. what is the frictional force between the crate and the ramp? A 25-kg crate is pulled up a ramp 25 m long and 3 m high by a constant force of 120 N that is applied parallel to the ramp. the crate starts from rest and has a velocity of 1.5 m/s when it reaches the top of the ramp. what is the frictional force between the crate and the ramp?

Explanation / Answer

from the data

sin theta = 3/25

theta = sin^-1 ( 3/25) = 6.89

Apply Newton second law

F- mgsin theta - fk = ma

F- mg sin tehta - ma = fk

-----------------------------------------------------------------------

v^2- u^2 = 2as

1.5^2 - 0^2 = 2 a( 25 m)

a= 0.045 m/s^2

fk = 120 N - 25 (9.8) sin6.89 - 25(0.045)

=89.48 N

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