Suppose both frequencies are changed to frequency f. The listener moves to point

Question

Suppose both frequencies are changed to frequency f. The listener moves to point Q and finds that he can hardly hear the sound, indicating destructive interference. Let f = 258 Hz and D is not given. How much further is point a from S_2 than it is from S_1? 0.715 m, 0.746 m, 0.665 m, 0.686 m The listener returns to point P and speaker2 is turned off. Speaker 1 broadcasts power P. What is the sound intensity (in w/m^2 that the listener 2.76 times 10 3.82 times 10^4 times 10dN 5, 46 times 10^14. How many decibels does this sound level have If the threshold of hearing is 10 w/m 85.8 dB 86.7 dB, 87.4 dB 84.4 dB A candle of height w is located a distance D from a concave spherical mirror of radius R. Let w m 0.020 m. D 4.00 m and R = 1.50 m. What is the focal length of the mirror? 0.85m, 0.90 m, 0.75 m, 0.80 m How far from the mirror will the image be? 0, 988 m, 1.054 m, 1.119 m, 0.923 m How tall will the image be? 0.0085 m, 0.0046 m, 0.0059 m, 0.0072 m The image will be: Real and upright, Real and inverted, virtual and upright, virtual and inverted.

Explanation / Answer

Solving15-18

Using mirror formula

1/f = 1/v + 1/u

Where

f is focal length

v is image's distance

u is object's distance

m = -v/u = hi/ho

Where m is magnication

hi is height of image

ho is height of object

R = f/2

15) 1.5/2 = 0.75m

16) v = 0.923m

17) 0.0046m

18) Real and inverted

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