In a two-slit interference experiment, a viewing screen is placed 5 meters direc

Question

In a two-slit interference experiment, a viewing screen is placed 5 meters directly behind two slits separated by 4 m. Coherent, monochromatic light of wavelength = 700 nm emerges (in phase) from the slits. (Assume the slit width is very small compared to the wavelength .)

Studying for a final, please please please post work

Physics 214* Sample Final Exam Spring 2010 The next two questions pertain to the following situation: In a two-slit interference experiment, a viewing screen is placed 5 meters directly behind two slits separated by 4 um. Coherent, monochromatic light of wavelength 700 nm emerges (in phase) from the slits. (Assume the slit width is very small compared to the wavelength 5 m. 24. what value of x on the screen does the largest-order intensity maximum occur (i.e., the one that is the farthest from the center line)? a. x 1.2 m b. x 4.4 m c. x 5.0 m d. x 9.0 m e. x 15.7 m 25. What happens to the separation between the existing intensity maxima on the screen as we increase the slit spacing? a. The separation decreases. b. The separation increases. c. There is no change.

Explanation / Answer

for maximum intensity,

sin(theta_n) = n * lambda / a

sin90 = n * 700 x 10^-9 / (4 x 10^-6)

n = 5.71

so last fringe is for n = 5

x = n lambda D / a

= 5 x 700 x 10^-9 x 5 / (4 x 10^-6)

x = 4.4 m

Ans(b)

25. y = lambda D / a

if we increase a then y will decrease.

Ans(a)

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