A 0.22-kg stone is held 1.2 m above the top edge of a water well and then droppe

Question

A 0.22-kg stone is held 1.2 m above the top edge of a water well and then dropped into it. The well has a depth of 5.1 m. Relative to the configuration with the stone at the top edge of the well, what is the gravitational potential energy of the stone-Earth system before the stone is released? The correct answer is not zero. J Relative to the configuration with the stone at the top edge of the well, what is the gravitational potential energy of the stone-Earth system when it reaches the bottom of the well? Your response differs from the correct answer by more than 10%. Double check your calculations. J What is the change in gravitational potential energy of the system from release to reaching the bottom of the well?

Explanation / Answer

part a:

initial height from the top edge of the well=1.2 m

so potentiale energy=mass*g*height=0.22*9.8*1.2=2.5872 J

part b:

at the bottom of the well, depth=-5.1 m

so potential energy=mass*g*height

=0.22*9.8*(-5.1)

=-10.996 J

part c:

change in gravitation potential energy=-10.996-2.5872=-13.5828 J

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