Why is it necessary to torque the mast slightly while the system is spinning? Wh

Question

Why is it necessary to torque the mast slightly while the system is spinning? Why don't we use Eq. 2 as the operative equation for this lab, instead of Eq. 3? What is the action/reaction partner force to the centripetal force? (Enter "up", "down", or "0" on each line.) What are the directions of the real net force and the fictitious force on a person in an elevator as the elevator car... ...starts climbing? ...slows its ascent? ...climbs with constant speed? ...starts descending? ...slows its descent? ...descends with constant speed? Why is question 4 included in a lab on circular motion, when elevators only undergo purely linear motion?

Explanation / Answer

Any motion in a curved path represents accelerated motion, and requires a force directed toward the center of curvature of the path. This force is called the centripetal force which means "center seeking" force. So it is a action force because it is produce by motion in a curved path . when acording to newton's third law of motion for every action there is an equal and opposite reaction so its reaction is centrifugal force equal and oposite direction.

Centripital force Fc = (m v2) / r

where m is mass of body, v is velocity of body and r is radius of path.

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