James and Ramon are standing 20.0 m apart on the slippery surface of a frozen po

Question

James and Ramon are standing 20.0 m apart on the slippery surface of a frozen pond. Ramon has mass 52.0 kg and James has mass 94.0 kg . Midway between the two men a mug of their favorite beverage sits on the ice. They pull on the ends of a light rope that is stretched between them. Ramon pulls on the rope to give himself a speed of 0.75 m/s .

Part A

What is James's speed?

Express your answer using two significant figures.

James and Ramon are standing 20.0 m apart on the slippery surface of a frozen pond. Ramon has mass 52.0 kg and James has mass 94.0 kg . Midway between the two men a mug of their favorite beverage sits on the ice. They pull on the ends of a light rope that is stretched between them. Ramon pulls on the rope to give himself a speed of 0.75 m/s .

Part A

What is James's speed?

Express your answer using two significant figures.

Explanation / Answer

given

mass of James mj = 94 kg, Ramon mass mr = 52 kg

they were standing at a distance of 20 m

initially all are at rest so the momentum of the system is zero

now the Ramon pulled on the rope with speed vr = 0.75 m/s

what about the James speed Vj =?

by conservation of momentum ( friction is zero -- frozen ond)

initial momentum = 0 kg m/s

final momentum is

   mr*vr+mj*vj = 0

substitute the values

   52*0.75+94*vj = 0

let james is on right side then

   94*Vj = 52*0.75

   Vj = 0.4149 m/s

so james will pull with a speed 0.4149 m/s

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