(29%) Problem 5: A horizontal force, F 75 N, and a force, F 10.7 N acting at an
ID: 1546410 • Letter: #
Question
(29%) Problem 5: A horizontal force, F 75 N, and a force, F 10.7 N acting at an angle of 0 to the horizontal, are applied to a block of mass m 39 The kg. coefficient of kinetic friction between the block and the surface is uk 0.2. The block is moving to the right Randomized Variables 75 F2 10.7 N m 39 kg Otheexpertta.com A 50% Part (a) Solve numerically for the magnitude of the normal force, FN in Newtons, that acts on the block if 6 30° Grade Summary Deductions 100% Potential sino 7 8 9 Submissions cos0 Attempts remaining 7 cotano asin 4 5 6 acos0 (59 per attempt) 1 2 3 atano acotan( Sinho detailed view cosh0 tanh00 cotanh0 0 Degrees O Radians Submit Feedback 0% deduction per feedback Hints: A 50% Part (b) Solve numerically for the magnitude of acceleration of the block, a in m/s2, if 6 30°Explanation / Answer
from the figure
N = F2*sin30 + mg
N = 10.7* sin30 + 3.9 * 9.8
N = 43.57 N
part b )
Fnet = F1 - F2costheta - friction force
friction force = mu*N = 0.2 * 43.57
m*a = 75 - 10.7cos30 - 8.714
3.9 *a = 75 - 10.7cos30 - 8.714
a = 14.6 m/s^2
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