A flatbed truck is carrying a 15.0-kg crate along a loci road. The coefficient o

Question

A flatbed truck is carrying a 15.0-kg crate along a loci road. The coefficient of friction between the crate and the bed is 0.370. What is the maximum acceleration the truck con has if the crate is to stay in place? A)78. m/s^2 B)3.73 m/s^2 C) 9.6 m/s^2 D) 3.63 m/s^2 E) 4.12 m/s^2 For uniform circular motion (that is, circular motion with constant speed), the velocity and acceleration vectors are a) parallel to each other at every point on the circle b) perpendicular to each other at every point on the circle c) opposite to each other at every point on the circle d) none of the above Recall that a car traveling with constant speed nu around a circle of radius r requires that the static frictional force provide the centripetal force. The relationship is mu s g = nu^2/r where mu_s is the coefficient of static friction. What is the maximum radius of the circle around which a car can travel at 33 m/s when the coefficient of static friction between the car's tires and the road is 0.62? a) 179 m b) 254 m c) 123 m d)221 m

Explanation / Answer

here,

m = 15 kg

uk = 0.37

the maximum accelration of truck , a = uk * g

a = 0.37 * 9.81 = 3.63 m/s^2

the maximum accelration that the truck can have if the crate is stay in place is D) 3.63 m/s^2

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