- C, D, B, C and D, A and C, A and D, A and B, B and D, B and C, A ,A and C, D,
ID: 1546833 • Letter: #
Question
- C, D, B, C and D, A and C, A and D, A and B, B and D, B and C, A ,A and C, D, B
(ii) If any of the charges feel 0 force, indicate it here.
A, B, C, D, None are 0
(iii) If a test charge of magnitude twice as large as the original test charge were placed at point A, how would the force it feels compare to the force felt by the original test charge when it was placed at point A?
1. same
2. twice as big
3. half as big
4. something else
Explain your reasoning.
(iv)How would the electric field measured at point A by the test charge in (iii) compare to the electric field measured at point A by the test charge in (i)?
1. same
2. twice as big
3. half as big
4. something else
Explain your reasoning.
---Select--- A B C D E F G H I J K
In the figure at the right are shown two settings of positive and negative charges. The setting on the left has two positive charges; the setting on the right has one negative charge and one positive charge. Each of the charges has the same magnitude.(i) In each setting, two positions are labeled. If a test charge were to measure the field at each position, rank the magnitude of the electric force the charge would measure at the four places. O-positive negative
Explanation / Answer
i) At B, the net field due to two +ve charges gets cancelled, so the net force at B=0.
At D, the net field due to the two charges gets added, so the net force will be greatest.
At A and C the fields due to each charge is perpendicular to the field due to other charge. So the net force will not be zero but it will also be less than that at D.
So the order is B:lowest A&C : equal D :highest
ii) The net force at B is zero, so the net force at B is also Zero.
iii)Field at A remains same and the Force is give by F = qEnet So the force will be twice.
iv)Electric field will be same
v)the net field will point in F direction.
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