On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball wit

Question

On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a 6 iron. The free-fall acceleration on the moon is 1/6 of its value on earth. Suppose he hits the ball with a speed of 26 m/s at an angle 60 above the horizontal.

1) How much farther did the ball travel on the moon than it would have on earth?

Express your answer to two significant figures and include the appropriate units.

2)For how much more time was the ball in flight?

Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

time of flight =2* Vo*sin thetha / a

at earth:
te = 2* 26*sin 60 / 9.8
=4.595 s

at moon:
tm = 2* 26*sin 60 / {(1/6)*9.8}
=27.57 s

range = Vo cos thetha * t

at earth :
Re = 26*cos 60 * 4.595
= 59.73 m

at moon:
Rm = 26*cos60 *27.57
=358.41 m

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