(8%) Problem 12: Consider the compound optical system shown in the diagram, wher

Question

(8%) Problem 12: Consider the compound optical system shown in the diagram, where two thin lenses of focal lengths 6-5 cm (left lens) and 42 cm (right lens are separated by a distance 29 cm. Otheexpertta.com 13% Part (a) If an object is placed a distance do f1 to the left of the first lens (the left lens), will the resulting image from the first lens be real or virtual, and inverted or upright? Final Correct Answer Student Answer Grade Real, Inverted 100% Not available until end date Grade Detail Correct Student Feedback see above Final Answer Credit 100% Submission History Answer Hints Feedback Totals 0% 0% Note: Feedback not accessed. 0% Virtual, Inverted 0% 0% Note: Feedback not accessed. 0% Real, Upright Upright 0% 0% Note: Feedback not accessed. 0% Virtual, 0% 0% 0% Real, Inverted 0% 0% Totals If a 13% Part (b) 2.9 cm tall object is placed as indicated in part (a), and the image formed is 0.88 cm tall, what is the magnification of the first lens? 13% Part (c) Using the information from part (b), calculate the image distance, in centimeters, from the first lens. 13% Part (d) Does the image formed by the first lens serve as a real or a virtual object for the second lens? 13% Part (e) What is the image distance, in centimeters, for the second lens? 13% Part (f What is the magnification of the second lens? A 13% Part (g What is the total magnification of this compound optical system? 13% Part (h) Is the image created by the second lens real or virtual? Is it upright or inverted?

Explanation / Answer

a)

When the object is placed a distance do>f1, image will be real and inverted.

b)

m1=h1i/h1o= -0.88/2.9 = -0.3034

c)

m1=h1i/ho = -d1i/d1o

-0.3=-d1i/d1o

d1o= d1i/0.3034

1/f1=1/d1o+1/d1i

1/6.5 = 1/(d1i/0.3054) + 1/d1i

d1i= 8.5cm

d)

Image formed by first lens will served as real image for second lens

e)

here do=29-8.5 = 21.5cm, f2=42cm

1/f2=1/d2o+1/d2i

1/42= 1/21.5 + 1/d2i

d2i= -44.05cm

f)

m=-d2i/d2o = -(44.05/8.5) = 5.18

g)

M= -d2i/d1o = -d2i/(d1i/0.3034) = -(-44.05)/(8.5/0.3) = 1.6

Or M=m1m2 = 0.3034*5.18

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