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The center of mass of a person may be determined by an arrangement such as the o

ID: 1549380 • Letter: T

Question

The center of mass of a person may be determined by an arrangement such as the one shown in the figure below. A light plank rests on two scales separated by a distance of d = 1.80 m and reading Fg1 = 465 N and Fg2 = 365 N. Determine the distance of the girl's center of mass from her feet. m A person is lying on her back on a board. The part of the board below her head sits upon a scale that measures a quantity marked F_g1. The part of the board below her feet sits upon a scale that measures a quantity marked F_g2, which is less than F_g1. The distance from the center of one scale to the center o fthe center scale is 1.8 m.
In m The center of mass of a person may be determined by an arrangement such as the one shown in the figure below. A light plank rests on two scales separated by a distance of d = 1.80 m and reading Fg1 = 465 N and Fg2 = 365 N. Determine the distance of the girl's center of mass from her feet. m A person is lying on her back on a board. The part of the board below her head sits upon a scale that measures a quantity marked F_g1. The part of the board below her feet sits upon a scale that measures a quantity marked F_g2, which is less than F_g1. The distance from the center of one scale to the center o fthe center scale is 1.8 m.
In m The center of mass of a person may be determined by an arrangement such as the one shown in the figure below. A light plank rests on two scales separated by a distance of d = 1.80 m and reading Fg1 = 465 N and Fg2 = 365 N. Determine the distance of the girl's center of mass from her feet. m A person is lying on her back on a board. The part of the board below her head sits upon a scale that measures a quantity marked F_g1. The part of the board below her feet sits upon a scale that measures a quantity marked F_g2, which is less than F_g1. The distance from the center of one scale to the center o fthe center scale is 1.8 m.
In m

Explanation / Answer

along vertical


Fg1 + Fg2 - W = 0


W = Fg1 + Fg2

W = 465+365 = 830 N


net torque about the feet = 0

W*Xcm = Fg1*L

830*Xcm = 465*1.8

Xcm = 1.008 m <<<<-------------answer from the feet

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