An object of height 2.6 cm is placed 25 cm in front of a diverging lens of focal

Question

An object of height 2.6 cm is placed 25 cm in front of a diverging lens of focal length 19 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length. Part (a) Find the location of the final image, in centimeters beyond the converging lens Numeric: A numeric value is expected and not an expression. s" = Part (b) What is the magnification of the final image? Include its sign to indicate its orientation with respect to the object. Numeric: A numeric value is expected and not an expression. m_total =

Explanation / Answer

1)

p=object distance
q=image distance
f=focal length (negative because diverging lens)
1/p+1/q=1/f
1/25+1/q=1/-19
q=-10.79cm

2)

magnification equation:
M=-q/p
=10.79/25
=0.4316 cm.

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