Young y = 0 at the top edge the well, what is the gravitational potential energy

Question

Young y = 0 at the top edge the well, what is the gravitational potential energy of the stone-Earth system when it reaches the bottom of the well? -12 J (c) What is the change in gravitational potential energy of the system from release to reaching the bottom of the well? -14.8224 J A daredevil on motorcycle leaves the end of a ramp with a speed of 37. m/s as in the figure below. If his speed is 35.7 m/s when he reaches the of the path, what is the maximum height that the reaches? friction and air resistance. m

Explanation / Answer

Vi = velocity at the time of launch = 37.8 m/s

Vf = velocity at the peak point = 35.7 m/s

h = height gained

using conservation of energy

initial KE = final KE + PE

(0.5) m Vi2 = (0.5) m Vf2 + mgh

(0.5) Vi2 = (0.5) Vf2 + gh

(0.5) (37.8)2 = (0.5) (35.7)2 + 9.8 h

h = 7.875 m

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