When the man stands 1.51 m in front of the mirror, the object is located at a di

Question

When the man stands 1.51 m in front of the mirror, the object is located at a distance p = +1.51 m = 151 cm. We are given that a real image is formed at the image distance of q = +18.7 cm. We find the focal length f of the mirror from the mirror equation, 1/f = 1/p + 1/q. Solving for the focal length, we obtain the following. f = pq/p + q for the product in the numerator, pq = cm^2, and for the sum in the denominator, p + q = cm, and thus for the focal length, we obtain f = pq/p + q = (cm^2/cm) = cm.

Explanation / Answer

p q = 151 x 18.7 = 2823.7 cm^2 .........Ans

p + q = 169.7 cm .........ans

f = pq / (p + q)

f = (2823.7) / (169.7)

f = 16.64 cm .......Ans

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