When the following oxidation-reduction reaction in acidic solution is balanced,

Question

When the following oxidation-reduction reaction in acidic solution is balanced, what is the lowest whole-number coefficient for K'(aq) ? K(s) + Cu^2+ (aq) + Cu(s) 1 2 3 4 5 When the following oxidation reduction reaction in acidic solution is balanced, what is the lowest whole-number coefficient for H*. and on which side of the balanced equation should it appear? Cr_2 Or^2- (aq) + CH_2 O(aq) right arrow Cr^3+ (aq) + HCOOH(aq) 1, reactant side 2, product side 6, product side 8, reactant side 14. reactant side When the following oxidation-reduction reaction in basic solution is balanced, what is the lowest whole-number coefficient for OH? Fe(OH)_2 (s) + H_2(g) right arrow Fe(s) + H_2 O(l) 0 1 2 3 4

Explanation / Answer

1) Cu+2 + 2e- = Cu

2K - 2e- = 2K+

Hence net eqn: Cu+2 + 2K = Cu + 2K+ , Hence whole num is 2

2) (Cr2O7)2- +14H+ + 6e- = 2Cr+3 + 7 H2O

[CH2O + H2O - 2e- = HCOOH + 2H+ ] x 3

net eqn :   (Cr2O7)2- + 8H+ + 3CH2O = 6H2O +3 HCOOH, Hence 8H+ on reactant side

3) Fe+2 + 2e- = Fe

H2 + 2OH- - 2e- = 2 H2O

net eqn : Fe+2 + H2 +2OH- = Fe + 2H2O, Hence 2 OH- in the reactants side

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