When the current in the portion of the circuit shown below is 1.90 A and increas

Question

When the current in the portion of the circuit shown below is 1.90 A and increases at a rate of 0.580 A/s, the measured voltage is ?Vab = 9.25 V. When the current is 1.90 A and decreases at the rate of 0.580 A/s, the measured voltage is ?Vab = 4.70 V. Calculate the values of L and R.

L =      H R =      ? When the current in the portion of the circuit shown below is 1.90 A and increases at a rate of 0.580 A/s, the measured voltage is ?Vab = 9.25 V. When the current is 1.90 A and decreases at the rate of 0.580 A/s, the measured voltage is ?Vab = 4.70 V. Calculate the values of L and R.

Explanation / Answer

Vab = Vr - Vl
and when it decreases
Vab = Vr + Vl

Added:
I assumed you know:
Vr = I * R
so
Vab = 4.7 = 1.9 * R - L * 0.58 ( equation 1 )
Vab = 9.25 =1.9 * R + L * 0.58 ( equation 2 )

L=4.13793

R=3.7368

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