When the current in the portion of the circuit shown below is 1.90 A and increas

Question

When the current in the portion of the circuit shown below is 1.90 A and increases at a rate of 0.580 A/s, the measured voltage is ?Vab = 9.25 V. When the current is 1.90 A and decreases at the rate of 0.580 A/s, the measured voltage is ?Vab = 4.70 V. Calculate the values of L and R.

L =      H R =      ? When the current in the portion of the circuit shown below is 1.90 A and increases at a rate of 0.580 A/s, the measured voltage is ?Vab = 9.25 V. When the current is 1.90 A and decreases at the rate of 0.580 A/s, the measured voltage is ?Vab = 4.70 V. Calculate the values of L and R.

Explanation / Answer

Va - [L*(di/dt)] - i*R = Vb => Va - Vb = i*R + [L*(di/dt)] when Vab = 9.25 V => Va - Vb = 9.25 V => 9.25 = 1.9*R + [L*0.58] => 1.9*R = 9.25 - 0.58*L also, when Vab = 4.7 V => Va - Vb = 4.7 V => 4.7 = 1.9 *R + [L*(-0.58)] => 4.7 = [9.25 - 0.58*L] - 0.58*L => L = 3.9224 H so, R = [9.25 -0.58*3.9224]/1.9 = 3.67 ohm

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