In the figure, a conducting rod of length L = 26.0 cm. moves in a magnetic field

Question

In the figure, a conducting rod of length L = 26.0 cm. moves in a magnetic field B of magnitude 0.410 T directed into the plane of the figure. The rod moves with speed v = 7.00 m/s in the direction shown. Which point, a or b, has a higher potential? a b Points a and b have the same potential. What is the magnitude Delta V of the potential difference between the ends of the rod? Express your answer in volts to at least three significant figures. What is the magnitude epsilon of the motional emf induced in the rod? Express your answer in volts to at least three significant figures.

Explanation / Answer

E)

As the rod moves in the direction indicated , using right hand rule , the direction of induced current comes out to be from point "a" to point "b"

since current travels from high potential to low potential , hence point "a" is at high potential

F)

L = length of rod = 26 cm = 0.26 m

Motional EMF is given as

E = BLv

E = (0.410) (0.26) (7)

E = 0.75 Volts

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