In the figure, a conducting rod of length L = 26.0 cm moves in a magnetic field

Question

In the figure, a conducting rod of length L = 26.0 cm moves in a magnetic field B of magnitude 0.500 T directed into the plane of the figure. The rod moves with speed v = 7.00 m/s in the direction shown.

When the charges in the rod are in equilibrium, which point, a or b, has an excess of positive charge?

-I am using the right hand rule: middle finger- magnetic field, index finger- velocity, thumb- force and I am getting that point a has excess but the answer is point b. Could you explain how you are using the right hand rule to solve for this? I would greatly appreciate.

Explanation / Answer

by using right hand rule 1

point the thumb of the right hand in the direction of v

the fingers in the direction of B,

a perpendicular to the palm points in the direction of F

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