In the figure, a conducting rod of length L = 26.0 c m moves in a magnetic field

Question

In the figure, a conducting rod of length L = 26.0cmmoves in a magnetic field B? of magnitude 0.520Tdirected into the plane of the figure. The rod moves with speed v = 4.00m/s in the direction shown. (Figure 1)

1) When the charges in the rod are in equilibrium, which point, a or b, has an excess of positive charge?

2) What is the direction of the electric field in the rod?

3) When the charges in the rod are in equilibrium, what is the magnitude

E of the electric field within the rod? express youur answer in volts per meter

Explanation / Answer

1) point b

2) from b to a

3) Fe = Fb

q*E = q*v*B

==> E = v*B = 4*0.52 = 2.08 V/m

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