The heat lost by the hot bolt is equal to the heat gained by the water in the ca
ID: 1553054 • Letter: T
Question
The heat lost by the hot bolt is equal to the heat gained by the water in the calorimeter. Use the equations provided above and what you know about heat to solve for the specific heat (C) of the steel. Show your work.
Mass of water : 10.5 g
Mass of bolt: 22 g
Specific heat: 4.184 J/gC
Difference in temp: (Ti -Tf) 29 - 20 = 9
Mass * specific heat * temp difference – 10.5 g * 4.184 J / g.C * 9 C = 391.7 J
What is the specific heat of steel from Table 1? Find the percent error for your calculated specific heat relative to this accepted value. Show your work.
Mass of the bolt: 22 g
Temp. difference: 82 – 29 = 53 C
Heat put out by bolt: 22 g * 4.184 J/gC * 53 C =1166
391.7=1166
Specific heat of the bolt = 0.336 J/gC
> > > What was the difference between your calculation and the actual specific heat of steel? How could you improve the experiment to reduce this error?
Explanation / Answer
We know that: heat transfer Q = m×Cp×T
Water:
Q=10.5×4.184×(29-20)=395.38 J
Bolt:
Q = 22×Cp×(82-29)
Cp= 395.38/(22×53)=0.339 J/g°c
Standard specific heat of carbon steel is 0.49 J/g°c
To improve experimental specific heat, we should reduce mass of bolts if temperature difference remain constant .
We should increase mass of water, or temperature difference . ( more cold water can be used)
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