REMARKS The number of loops, N, can\'t be arbitrary because there must be a forc
ID: 1553296 • Letter: R
Question
REMARKS The number of loops, N, can't be arbitrary because there must be a force strong enough to turn the coil.QUESTION If the frequency is doubled, the maximum induced emf is multiplied by . PRACTICE IT Use the worked example above to help you solve this problem. An AC generator consists of eight turns of wire, each having area A = 0.0850 m2, with a total resistance of 11.9 . The loop rotates in a magnetic field of 0.463 T at a constant frequency of 57.1 Hz. (a) Find the maximum induced emf. V
(b) What is the maximum induced current? A
(c) Determine the induced emf and current as functions of time. e m f = ( V)sin(t) I = ( A)sin(t) =
(d) What maximum torque must be applied to keep the coil turning? N · m EXERCISE HINTS: GETTING STARTED | I'M STUCK! An AC generator is to have a maximum output of 310 V. Each coil has an area of 0.131 m2 and a resistance of 15.6 and rotates in a magnetic field of 0.646 T with a frequency of 41.7 Hz, with the axis of rotation perpendicular to the direction of the magnetic field. (a) How many turns of wire should the coil have to produce the desired emf? N = turns
(b) Find the maximum current induced in the coil. Imax = A
(c) Determine the induced emf as a function of time. = ( V)sin t REMARKS The number of loops, N, can't be arbitrary because there must be a force strong enough to turn the coil.
QUESTION If the frequency is doubled, the maximum induced emf is multiplied by . PRACTICE IT Use the worked example above to help you solve this problem. An AC generator consists of eight turns of wire, each having area A = 0.0850 m2, with a total resistance of 11.9 . The loop rotates in a magnetic field of 0.463 T at a constant frequency of 57.1 Hz. (a) Find the maximum induced emf. V
(b) What is the maximum induced current? A
(c) Determine the induced emf and current as functions of time. e m f = ( V)sin(t) I = ( A)sin(t) =
(d) What maximum torque must be applied to keep the coil turning? N · m EXERCISE HINTS: GETTING STARTED | I'M STUCK! An AC generator is to have a maximum output of 310 V. Each coil has an area of 0.131 m2 and a resistance of 15.6 and rotates in a magnetic field of 0.646 T with a frequency of 41.7 Hz, with the axis of rotation perpendicular to the direction of the magnetic field. (a) How many turns of wire should the coil have to produce the desired emf? N = turns
(b) Find the maximum current induced in the coil. Imax = A
(c) Determine the induced emf as a function of time. = ( V)sin t REMARKS The number of loops, N, can't be arbitrary because there must be a force strong enough to turn the coil.
QUESTION If the frequency is doubled, the maximum induced emf is multiplied by . PRACTICE IT Use the worked example above to help you solve this problem. An AC generator consists of eight turns of wire, each having area A = 0.0850 m2, with a total resistance of 11.9 . The loop rotates in a magnetic field of 0.463 T at a constant frequency of 57.1 Hz. (a) Find the maximum induced emf. V
(b) What is the maximum induced current? A
(c) Determine the induced emf and current as functions of time. e m f = ( V)sin(t) I = ( A)sin(t) =
(d) What maximum torque must be applied to keep the coil turning? N · m EXERCISE HINTS: GETTING STARTED | I'M STUCK! An AC generator is to have a maximum output of 310 V. Each coil has an area of 0.131 m2 and a resistance of 15.6 and rotates in a magnetic field of 0.646 T with a frequency of 41.7 Hz, with the axis of rotation perpendicular to the direction of the magnetic field. (a) How many turns of wire should the coil have to produce the desired emf? N = turns
(b) Find the maximum current induced in the coil. Imax = A
(c) Determine the induced emf as a function of time. = ( V)sin t
Explanation / Answer
(a)
maximum induced emf is
e= NA Bw
= N A B ( 2pi f)
=8(0.0850) ( 0.463) ( 2pi ( 57.1)
=112.89 V
(b)
Imax = e/R = 112.89 V/11.9
=9.48 A
(c)
e= emax sin ( wt)
=112.89 V sin ( 2pi (57.1) t
=112.89 V sin(358.58 t)
(d)
I = Imax sin wt
= 9.48 sin (358.58 t)
(e)
T = uB sin theta
= NIA B sin theta
= 8 ( 9.48)(0.0850) ( 0.463) sin 90
=2.98 Nm
As per guide lines I worked first problem, please post remining questions in the next post
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