ulus eth Edition Edition C Stewart Calculus Early Mylab & Mastering aty PHrs 211

Question

ulus eth Edition Edition C Stewart Calculus Early Mylab & Mastering aty PHrs 211 spring17-smNNETT I Activiti es and Due Dates I HW: Momentum Impulse and Collisions U 4/5/2017 11:00 PM 66.2100 4/2/2017 0134 AM Peradic Table Question of 19 Sapling Learning An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only a rope and a the rope is too s In a last ditch the astronaut throws his bag of tools in the directon of mooon away rom the space station). The has mass of 124 kg the bag tools has an minimum away from the station at 2.40 m/s initially, what is the drifting final speed of the bag of tools (with respect to the space station) that will keep the astronaut from away forever? 19.8 m/s There is a hint available! divider bar again to hide the hint. o Previous Check Answer 0 Next Eu

Explanation / Answer

Answer:-

ma =Mass of Astronaut = 124 Kg

mb =Mass of tool bag = 10 kg

u1 =u2 = 2.4 m/s this is condier velocity of astronaut before throw the ball.

before throwing a tool bag the velocity of astonaut and tool bag is same =2.4 m/s

we have to find the final velocity of the tool bag. V2= ?

we have to consider the V1 is the velocity of astronaut after throwing a tool bag , which will be zero .

V1 =0

Given condition is seem related to linear momentum

so we have to write first the equation of conservation of linear momentum

m1*u1+m2*u2 = m1*V1 +m2*V2

now plug in the values in above formula.

124*2.4+10*2.4 = 124*0 +10*V2

V2 =32.16 m/s

Hence the minimum final speed of the tool bag will be 32.16 m/s

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