A One-Dimensional Inelastic Collision Block 1, of mass m 1 = 1.90 kg , moves alo

Question

A One-Dimensional Inelastic Collision

Block 1, of mass m1 = 1.90 kg , moves along a frictionless air track with speed v1 = 29.0 m/s . It collides with block 2, of mass m2 = 55.0 kg , which was initially at rest. The blocks stick together after the collision. (Figure 1)

Part B

Find vf, the magnitude of the final velocity of the two-block system.

Express your answer numerically.

Part C

What is the change K=KfinalKinitial in the two-block system's kinetic energy due to the collision?

Express your answer numerically in joules.

Explanation / Answer

m1 = 1.9 kg , m2 = 55 kg , v1 = 29 m/s, v2 =0

from conservation of momentum

m1u1 +m2u2 = (m1+m2)v

1.9*29 +55* 0 = (1.9+55)*v

v = 0.968 m/s

(b) K=KfinalKinitial

K= 0.5*(m1+m2)v^2 - 0.5m1v1^2 -0.5m2v2^2

= 0.5(1.9+55)*0.968^2 -0.5*1.9*29^2 -0

= -772.3 J

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