A student wishes to suspend a square loop of wire at a 45 degree angle to the ve
ID: 1553660 • Letter: A
Question
A student wishes to suspend a square loop of wire at a 45 degree angle to the vertical using the Earth's magnetic field. The geometry is depicted in (Figure 1) At the student's location the Earth's magnetic field has a magnitude of 5.0 times 10 -5T and is oriented 60.0 degree below horizontal. All of the counterclockwise torque acting on the loop arises from the magnetic force on the bottom side of the square. Is the current in the loop clockwise or counterclockwise, as viewed from above? Clockwise Counterclockwise The loop is a square with mass m = 0.0079 kg and sides of length L = 0.20 m. How much current must flow through the loop to suspend it as shown? Express your answer to two significant figures and include appropriate units.Explanation / Answer
A) clockwise
B) In the equilibrium, net torque is zero.
Tnet = 0
m*g*(w/2)*sin(45) - F*w*sin(105) = 0
F = m*g*sin(45)/(2*sin(105))
B*I*L*sin(90) = m*g*sin(45)/(2*sin(105))
I = m*g*sin(45)/(2*B*L*sin(105))
= 0.0079*9.8*sin(45)/(2*5*10^-5*0.2*sin(105))
= 2834 A
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