A planet revolves around its star (in a circular orbit) once every 1.5 years at

Question

A planet revolves around its star (in a circular orbit) once every 1.5 years at 20km/s, find A) the angular speed of this planet in rad/sec, B) the angle through which the planet will revolve in one Earth year, and C) the distance in meters between the planet and it's star A planet revolves around its star (in a circular orbit) once every 1.5 years at 20km/s, find A) the angular speed of this planet in rad/sec, B) the angle through which the planet will revolve in one Earth year, and C) the distance in meters between the planet and it's star A planet revolves around its star (in a circular orbit) once every 1.5 years at 20km/s, find A) the angular speed of this planet in rad/sec, B) the angle through which the planet will revolve in one Earth year, and C) the distance in meters between the planet and it's star

Explanation / Answer

(A) w = 2pi / T

= 2pi / (1.5 x 365 x 24 x 3600 s)

= 1.328 x 10^-7 rad/s

(B) theta = w t = (1.328 x 10^-7 rad/s) (1 x 365 x 24 x 3600 s)

= 4.19 rad Or 240 deg

(C) v = w r

20 x 10^3 m /s = (1.328 x 10^-7 rad/s) (r)

r = 1.506 x 10^11 m

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