What is the net force exerted by these two charges on a third charge q 3 = 45.0

Question

What is the net force exerted by these two charges on a third charge q3 = 45.0 nC placed between q1and q2 at x3 = -1.215 m ?

Forces in a Three-charge system Coulomb's law for the magnitude of the force F between two particles with charges C and Q separated by a distance d is where K 1 4 Ten and Eo 8.854 x 10 12 C2/(N m2) is the permittivity of free space. Consider two point charges located on the x axis one charge, q1 16.0 nC s located at 21 1.695 m the second charge, q2 31.0 nC s at the origin (a 0.0000) previous l 11 of 24 I next Part A What is the net force exerted by these two charges on a third charge q3 *45.0 nC placed between q1 and 92 at 3 1.215 m Your answer may be positive or negative, depending on the direction of the force Express your answer numerically in newtons to three significant figures Force on E Submit Hints My Answers Give Up Review Part Provide Feedback Continue

Explanation / Answer

r13 = -1.215 - (-1.695) = 0.48m

r23 = 0 - (-1.215) = 1.215 m

F13 = k q1 q3/(r13)²

F13 = - 9E9 (16 E-9)(45 E-9)/(0.48)²

F13 = -2.8425 E-5 N


F23 = k q2 q3/(r23)²

F23 = - 9E9 (31 E-9) (45 E-9)/(1.215)²

F23 = - 0.8504 E-5 N


F_resultant = F13 + F23 = -2.8425 E-5 N - 0.8504 E-5 = -3.6829 E-5 N

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