What is the net force exerted by these two charges on a third charge = 54.5nC pl
ID: 2090292 • Letter: W
Question
What is the net force exerted by these two charges on a third charge = 54.5nC placed between and at = -1.190m? Your answer may be positive or negative, depending on the direction of the force Coulomb's law for the magnitude of the force between two particles with charges and separated by a distance is , where , and is the permittivity of free space. Consider two point charges located on the x axis: one charge, = -20.0nC , is located at = -1.660m ; the second charge, = 36.0nC , is at the origin . Please solve I have tried using the formula and am not getting the right answer..Explanation / Answer
so the - charge will pull the third charge to the left and the second + charge will push the charge to the left as well so the forces add
F = F1 + F2 = 9E9*54.5E-9*(20.0E-9/(1.66-1.19)^2 + 36.0E-9/1.19^2)=5.69E-5 N
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