A coil is suspended around an axis which is co-linear with the axis of a bar mag

Question

A coil is suspended around an axis which is co-linear with the axis of a bar magnet. The coil is connected to a resistor with ends labeled a and b. The bar magnet moves from right to left with North and South poles labeled in the figure. Using Lenz's law, what is the direction of the induced magnetic field in the coil and the direction of the induced current in the resistor R when the bar magnet is moving right to left? 1. The induced magnetic field is zero and the induced current is zero. 2. The induced magnetic field is zero and the induced current flows from b through R to a(leftarrow I). 3. The induced magnetic field is right to left (B_induced) and the induced current flows from a through R to b (I rightarrow). 4. The induced magnetic field is left to right (B_induced) and the induced current flows from a through R to b (I rightarrow). 5. The induced magnetic field is zero and the induced current flows from a through R to b (I rightarrow). 6. The induced magnetic field is left to right (B_induced) and the induced current flows from b through R to a (leftarrow I). 7. The induced magnetic field is left to right

Explanation / Answer

the magnetic of the magnetic is towards left

as the magnetic moves to left, the magnetic flux through the coil increases

according to lenz's law,

the induced current always opposes the change in flux

the induced magnetic field due to the induced current is to the right

the induced current is from b through R to a

OPTION 6 , 7

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.