A liquid of density 1.39 × 103 kg/m3 flows steadily through a pipe of varying di
ID: 1557604 • Letter: A
Question
A liquid of density 1.39 × 103 kg/m3 flows steadily through a pipe of varying diameter and height. At location 1 along the pipe the flow speed is 9.21 m/s and the pipe diameter is 12.9 cm. At location 2 the pipe diameter is 17.5 cm. At location 1 the pipe is 8.79 m higher than it is at location 2. Ignoring viscosity, calculate the difference between the fluid pressure at location 2 and the fluid pressure at location 1. Please make sure you have every value you use clearly defined. I have spent too much time trying to figure out one value in some answers on here. Thanks!
Explanation / Answer
Apply equation of continuity
A1 v1 = A2 v2
v2 = A1/A2 * v1 = d1^2/ d2^2 * v1
Apply Bernoulis equation
p2 + rho gh2 + 1/2 * rho v2^2 = p1 + rho g h1 + 1/2 * rho v1^2
p2-p1 = ( 1.39 * 10^3) ( 9.81) ( 8.79) + 1/2 * 1.39 * 10^3 ( 9.21)^2 ( 1- ( 12.9/17.5)^4
=119859.561--41546.2
=78313.361 Pa
=78.3 kPa
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