When first launched, the Hubble Space Telescope (HST) sent back blurred images.

Question

When first launched, the Hubble Space Telescope (HST) sent back blurred images. The HST primary mirror is 2.4 m in diameter, spherical, and concave with a design radius of curvature of 21.5 m. Using the mirror equation and the image distance of 10.7 m, could this design be the source of spherical aberration? Show how if it is true. When first launched, the Hubble Space Telescope (HST) sent back blurred images. The HST primary mirror is 2.4 m in diameter, spherical, and concave with a design radius of curvature of 21.5 m. Using the mirror equation and the image distance of 10.7 m, could this design be the source of spherical aberration? Show how if it is true. When first launched, the Hubble Space Telescope (HST) sent back blurred images. The HST primary mirror is 2.4 m in diameter, spherical, and concave with a design radius of curvature of 21.5 m. Using the mirror equation and the image distance of 10.7 m, could this design be the source of spherical aberration? Show how if it is true. When first launched, the Hubble Space Telescope (HST) sent back blurred images. The HST primary mirror is 2.4 m in diameter, spherical, and concave with a design radius of curvature of 21.5 m. Using the mirror equation and the image distance of 10.7 m, could this design be the source of spherical aberration? Show how if it is true. 5, (15) BONUS. When first launched the Hubble Space Telescope eas spherical age 1 NAME images. The HST primary mirror is 2.4 min diameter, n be them Using thod led hereas r) produced bl pace Telescope (1 with a machined radius ofcurvature of21 ere as spherical and concave mode distance of 10.7 m, could this design be the .5 m. e source of spherical aberration? Prove howthis could ing the mirro e mirror equation and the ma source be the case:

Explanation / Answer

ANS : 1/f = 1/u + 1/v

         Given : R = 21.5 m . i.e, f = R/2 = 10 .75 m

                    V = 10.70 m

          Now , 1/u = 1/f - 1/v

                    1/ u = 1 / 10.75 - 1/ 10. 70

                    1 /u = 0.0930    -   0.0934

                    1 /u = - 0.0004

                      u = - 1 / 0.0004

                      u = - 2500 m

therefore , for spherical aberration the object is placed at 2500m away from the leftside of the mirror .

if the collimated beam were tilted to shift the focus to an off-axis point for the system designed to be aberration free for the on-axis collimated beam, there in general will be a small aberration (including coma). To focus an on-axis collimated beam without aberration calls for a plano-convex lens (as in Youval's answer) whose curved surface is nearest the focus and which is a hyperbola of revolution about the optic axis.

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