Print Calculator Periodic Table Question 2 of 12 Sapling Learning The wheels of

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Print Calculator Periodic Table Question 2 of 12 Sapling Learning The wheels of a wagon can be approximated as the combination of a thin outer hoop, of radius m and mass 5.27 kg, and two thin crossed rods of mass 8.23 each. would like to wheels with uniform disks that are material a replace the per cubic meter. made of a with density of kilograms If the new wheel is to have the same moment ofinertia about its center as the old wheel about its center, what should the radius the disk be? Number 0.0525 m o Previous go Give Up & View Solution 2 Check Answer 0 Next Ext Hint

Explanation / Answer

Moment of inertia of wheel + rods is I1 = (M*R^2) + (1/12)*m*(2R)^2*2

I1 = (5.27*0.58^2)+((1/12)*8.23*(2*0.58)^2*2)

I1 = 3.62 kg-m^2

moment of inertia of disk is I2 = 0.5*m*R^2

mass of the disc is m = density *Volume = 6910*(pi*R^2*h) = 6910*3.142*r^2*0.0525

then I2 = 0.5*6910*3.142*r^2*0.0525*r^2

but given that I1 = I2

3.62 = 0.5*6910*3.142*r^2*0.0525*r^2

r = 0.282 m

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